Shardul Thakur has performed brilliantly in the second test so far. In the first innings (India vs South Africa), he sent 7 batsmen of South Africa to the pavilion. This is the best performance by an Indian bowler on the field. Due to this, Team India was successful in preventing South Africa from taking a big lead in the first innings. In the second innings on Wednesday, he made a significant contribution by playing a good inning with the bat as well. Team India's lead is more than 200 runs.
Shardul Thakur was dismissed in the second innings after scoring 28 runs in 24 balls. He hit 5 fours and a six. That is, he scored 26 runs from the boundary. He hit 2 fours in one over from fast bowler Marco Jensen. Seeing his fours, Virat Kohli, Mayank Agarwal, batting coach Vikram Rathor, sitting in the dressing room, could not stop laughing. Coach Rahul Dravid also clapped. Shardul has played more than 50 runs in 8 innings of 5 Tests before this match 3 times. Highest innings of 67 runs.
Average good even in first class
Shardul Thakur has also done well in first-class cricket with both bat and ball. Before this match, he has scored 1458 runs in 92 innings of 67 matches at an average of 17. Has scored 9 fifties. Played big innings of 87 runs. Apart from this, he has also taken 223 wickets at an average of 28. He has achieved the feat of taking 5 wickets 12 times. His best performance has been 6 wickets for 31 runs.
Team India has scored 245 runs for 9 wickets in the second innings till the time of writing the news. His total lead has become 218 runs. Hanuma Vihari is playing on 20 runs. India scored 202 and South Africa 229 in the first innings.